中学生网络课堂本课配套习题挑战模式1/5
单选题
难度系数：
1.SiO2属于酸性氧化物的理由主要是
| A: 硅是非金属元素 |
| B: SiO2对应的水化物是可溶性弱酸 |
| C: SiO2能与强碱反应生成盐和水 |
| D: SiO2不能与酸反应 |
一次做对，真牛！
+5奖励规则>
- 提示1：5bm26Z2e5omA5pyJ55qE6Z2e6YeR5bGe5YWD57Sg55qE5rCn5YyW54mp6YO95piv6YW45oCn5rCn5YyW54mp44CC
- 答案：Qw==
5LqM5rCn5YyW56GF6Jm954S25LiN5LiO5rC05Y+R55Sf5Y+N5bqU77yM5omA5a+55bqU55qE6YW45Lmf5bCx5piv56GF6YW477yM5Lmf5bm26Z2e5Y+v5rq25oCn6YW477yM5L2G5a6D6IO95aSf5LiO5by656Kx5Y+R55Sf5Y+N5bqU77yM5omA5Lul5bGe5LqO6YW45oCn5rCn5YyW54mp44CC5bqU5b2T6YCJ5oupQ+mhueOAgg==
本课配套习题挑战模式2/5
单选题
难度系数：
2.有关二氧化硅的叙述不正确的是
| A: 与所有的酸都反应 |
| B: 能与强碱反应 |
| C: 属于酸性氧化物 |
| D: 在一定条件下能与生石灰反应 |
一次做对，真牛！
+5奖励规则>
- 提示1：5LqM5rCn5YyW56GF5Y+v5Lul5LiO5rCi5rCf6YW45Y+N5bqU77yM5Y+v5Lul5LiO5aSn5aSa5pWw55qE5by656Kx5Y+R55Sf5Y+N5bqU77yb
- 提示2：55Sf55+z54Gw55qE5Li76KaB5oiQ5YiG5piv5rCn5YyW6ZKZ44CC
- 答案：QQ==
5LqM5rCn5YyW56GF5Y+v5Lul5LiO5rCi5rCf6YW45Y+N5bqU77yM5L2G6L+Z5piv5Liq54m55q6K55qE5Y+N5bqU77yM5bm26Z2e5LiO5omA5pyJ6YW46YO95Y+v5Lul5Y+R55Sf5Y+N5bqU77ybQemhuemUmeivr++8mzxicj7kuozmsKfljJbnoYXlj6/ku6XkuI7lpKflpJrmlbDnmoTlvLrnorHjgIHnorHmgKfmsKfljJbnianlj5HnlJ/lj43lupTvvIzlsZ7kuo7phbjmgKfmsKfljJbnianvvIznlJ/nn7PngbDnmoTkuLvopoHmiJDliIbmmK/msKfljJbpkpnvvIzlj6/ku6XkuI7kuozmsKfljJbnoYXlnKjpq5jmuKnkuIvlj5HnlJ/lj43lupTjgILlm6DmraRC44CBQ+OAgUTmraPnoa7jgII8YnI+5pys6aKY6YCJ5oupQemhueOAgg==
本课配套习题挑战模式3/5
单选题
难度系数：
3.下列关于CO2和SiO2性质的说法中，不正确的是
| A: CO2通入到水玻璃中可以得到硅酸 |
| B: CO2与SiO2在物理性质上差别很大 |
| C: SiO2与CaCl2溶液不反应，而CO2通入CaCl2溶液中可得到白色沉淀 |
| D: CO2和SiO2都是酸性氧化物，都能与NaOH溶液反应 |
一次做对，真牛！
+5奖励规则>
- 提示1：5rq25ray55qE5Y+N5bqU5LiA6Iis6YO95Lya56ym5ZCI4oCc5by65Yi25byx4oCd55qE5Y6f5YiZ44CC
- 提示2：56Kz6YW455qE6YW45oCn6KaB5by65LqO56GF6YW444CC
- 答案：Qw==
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
本课配套习题挑战模式4/5
单选题
难度系数：
4.下列说法正确的是
| A: SiO2不与HNO3、H2SO4等所有酸反应 |
| B: CO2和SiO2的对应水化物都是酸，其酸性碳酸比硅酸弱 |
| C: CO2与SiO2均是酸酐，溶于水均得到相应的酸 |
| D: 木炭、活性炭、硅藻土、硅胶都可作吸附剂 |
一次做对，真牛！
+5奖励规则>
- 提示1：5LqM5rCn5YyW56GF5piv6YW46YWQ77yM5L2G5a6D5LiN6IO95LiO5rC05Y+N5bqU44CC
- 提示2：6YW45oCn77ya56Kz6YW4Jmd0O+ehhemFuOOAgg==
- 答案：RA==
5LqM5rCn5YyW56GF5LiN5LiO5aSn5aSa5pWw55qE6YW45Y+N5bqU77yM5L2G5piv5Y+v5Lul5LiO5rCi5rCf6YW45Y+R55Sf5LiA5Liq54m55q6K5Y+N5bqU77yM5pWFQemhuemUmeivr++8mzxicj7kuozmsKfljJbnoYXlr7nlupTnmoTphbjkuLrnoYXphbjvvIzlhbbphbjmgKfmr5TnorPphbjlvLHvvJvkvYbkuozmsKfljJbnoYXkuI3og73kuI7msLTlj5HnlJ/lj43lupTjgII8YnI+5pWFQuOAgUPplJnor6/vvJs8YnI+57u85LiK77yM6YCJ5oupROmhueOAgg==
本课配套习题挑战模式5/5
单选题
难度系数：
5.将Ca(HCO3)2和SiO2的混合物在高温下加热，充分反应后，所得固体的质量为原混合物质量的一半，则原混合物中Ca(HCO3)2与SiO2物质的量之比及所得固体的成分分别是
| A: 6:5 CaO和CaSiO3 |
| B: 5:6 CaSiO3和SiO2 |
| C: 6:5 CaO、SiO2和CaSiO3 |
| D: 无法判断 |
一次做对，真牛！
+5奖励规则>
- 提示1：5pys6aKY55qE6Kej562U5pa55rOV5aSa56eN5aSa5qC377yM5L2G5piv6KaB55+l6YGT6LSo6YeP5YeP6L2755qE5Y6f5Zug77yaPGltZyB3aWR0aD0yNzIgaGVpZ2h0PTM2IHNyYz0iaHR0cHM6Ly9wMi5xaW5nZ3VvLmNvbS9HMS9NMDAvMDUvN0EvckJBQ0UxWkJsUGVobXFhWUFBQUVfTVNaUVJVMzA0LnBuZyI+44CC6ICM5rCn5YyW6ZKZ5LiO5LqM5rCn5YyW56GF55qE5Y+N5bqU5piv5LiN5b2x5ZON5L2T57O76LSo6YeP55qE44CC
- 提示2：5qC55o2u5Y+N5bqU77yM5q+PMW1vbOWPjeW6lOi0qOmHj+WHj+i9uzE4KzQ0w5cyPTEwNu+8jOWvueW6lOeahOWPjeW6lOS5i+WJjeeahOWbuuS9k+WwseW6lOivpeaYrzEwNueahOS6jOWAje+8jOS5n+WwseaYrzIxMu+8jOWFtuS4reeis+mFuOawoumSmeWNoDFtb2zjgII=
- 答案：QQ==
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