本课配套习题挑战模式1/5

A: 0.8A |
B: 0.16A |
C: 0.52A |
D: 1.28A |
- 提示1:5bm26IGU55S16Lev55S15rWB54m554K5
- 答案:RA==
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
本课配套习题挑战模式2/5
A: 3:5 |
B: 5:3 |
C: 2:5 |
D: 5:2 |
- 提示1:5bm26IGU55S16Lev55S15rWB54m554K5
- 答案:RA==
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
本课配套习题挑战模式3/5
一位同学家装有40瓦灯2盏,60瓦电视机一台,110瓦电冰箱一台,若他家再增添一个电饭锅,用电器同时工作时,干路中的总电流将()
A: 变小 |
B: 变大 |
C: 不变 |
D: 条件不足,无法判断 |
- 提示1:PHA+5bm26IGU55S16Lev5Lit5bmy6Lev55S15rWB562J5LqO5ZCE5pSv6Lev55S15rWB5LmL5ZKMPC9wPg==
- 答案:Qg==
PHA+5bm26IGU55S16Lev5Lit5ZCE55So55S15Zmo5LmL6Ze054us56uL5bel5L2c5LiN5Lya5LqS55u45b2x5ZON77yM5Y+I55Sx5LqO5bm26IGU55S16Lev5Lit5bmy6Lev55S15rWB562J5LqO5ZCE5pSv6Lev55S15rWB5LmL5ZKM77yM5omA5Lul5b2T5a625bqt55S16Lev5Lit5ZCM5pe25bel5L2c55qE55So55S15Zmo5pWw55uu5aKe5Yqg5pe277yM5oC755S15rWB5Y+Y5aSn77yM5pWF6YCJQi48L3A+
本课配套习题挑战模式4/5

A: 整理器材,结束实验 |
B: 换用不同规格的小灯泡,再测出几组电流值 |
C: 分析数据,得出结论 |
D: 换用电流表的另一量程,再测出一组电流值 |
- 提示1:5LiA5qyh5a6e6aqM5b6X5Ye657uT6K6677yM5YW35pyJ5YG254S25oCn
- 答案:Qg==
5LiA5qyh5a6e6aqM5b6X5Ye657uT6K6677yM5YW35pyJ5YG254S25oCn44CC5Li65L2/57uT6K666YG/5YWN5YG254S25oCn77yM5YW35pyJ5pmu6YGN5oSP5LmJ77yM6ZyA5o2i55So5LiN5ZCM6KeE5qC855qE5bCP54Gv5rOh77yM5YaN5rWL5Ye65Yeg57uE55S15rWB5YC844CC5a+554Wn5ZCE6YCJ6aG577yMQuato+ehru+8jOmAieWhq0LjgILnlLHkuo7mjaLnlKjnlLXmtYHooajkuI3og73mlLnlj5jnlLXot6/kuK3nlLXmtYHnmoTlpKflsI/vvIzmlYVE6YCJ6aG55LiN56ym5ZCI5a6e6aqM6KaB5rGC77yM6ZSZ6K+v44CC5pWF6YCJQi4=
本课配套习题挑战模式5/5
在下图所示的电路中,电源电压保持不变。闭合电键S,两只电流表的指针偏离零刻度线的角度恰好相同,则电流表A1和电流表A2所用量程分别为()
A: 都是0.6A |
B: 都是3A |
C: A1是0.6A,A2是3A |
D: A1是3A,A2是0.6A |
- 提示1:PHA+5q2k55S16Lev5Li65bm26IGU55S16LevPC9wPg==
- 提示2:PHA+5bm26IGU55S16Lev55S15rWB55qE54m554K5PC9wPg==
- 答案:Qw==
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