中学生网络课堂本课配套习题挑战模式1/6
单选题
难度系数：
1.
下列说法中，正确的是（ ）
| A: 电功率越大，电流做功越快，电路中产生的热量一定越多 |
| B: W=I2Rt ， W= |
| C: 在不是纯电阻的电路中，W<Q |
| D: 焦耳定律Q=I2Rt适用于任何电路 |
适用于任何电路
一次做对，真牛！
+5奖励规则>
- 提示1：PHA+55S15Yqf5piv6KGo56S655S15rWB5YGa5Yqf55qE5aSa5bCR77yM55S15Yqf546H5piv6KGo56S655S15rWB5YGa5Yqf55qE5b+r5oWi77yM54Sm6ICz5a6a5b6L5piv6KGo56S655S15rWB5Lqn55Sf55qE54Ot6YeP55qE5aSa5bCRLjwvcD4=
- 答案：RA==
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
本课配套习题挑战模式2/6
单选题
难度系数：
2.
某同学利用如图所示电路，测量额定电压为2.5V小灯泡的额定功率，下列说法错误的是（ ）
| A: 闭合开关前，滑片P应滑到B端 |
| B: 闭合开关后，小灯泡不发光，一定是小灯泡灯丝断了 |
| C: 当电压表示数为2.5V时，测出通过小灯泡的电流，可算出小灯泡的额定功率 |
| D: 实验还可得知，小灯泡的实际功率越大，小灯泡越亮 |
一次做对，真牛！
+5奖励规则>
- 提示1：PHA+54Gv5rOh5LiN5Y+R5YWJLOWPr+iDveaYr+Wwj+eBr+azoeefrei3ryzov5jlj6/og73mmK/mu5Hliqjlj5jpmLvlmajmjqXlhaXnlLXot6/nlLXpmLvlpKrlpKc8L3A+
- 答案：Qg==
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
本课配套习题挑战模式3/6
单选题
难度系数：
3.
如图甲所示是伏安法测定小灯泡电阻、功率的实验电路图. 小灯泡正常工作时，两电表的示数如图乙所示，则下列说法不正确的是（ ）
| A: 在连接电路时，应将开关断开，并将滑动变阻器值调至最大值 |
| B: 小灯泡的额定功率为0.72W，此时的电阻为8Ω |
| C: 如果将滑片P向a端滑动，则电压表的示数将变大 |
| D: 如果将滑片P向b端滑动，则小灯泡的实际功率将大于额定功率 |
一次做对，真牛！
+5奖励规则>
- 提示1：PHA+5byA5YWz6Zet5ZCI5YmN5bCG5ruR5Yqo5Y+Y6Zi75Zmo6Zi75YC86LCD5Yiw5pyA5aSn77yM5Y+v5Lul5L+d5oqk55S16LevPC9wPg==
- 提示2：PHA+55Sx5Zu+55+l5q2k5pe255S15rWB5Li6MC4zQe+8jOeUteWOi+S4ujIuNFbvvIzmoLnmja7lhazlvI9SPVUvSe+8jOWPr+W+l+eBr+azoeeUtemYuzwvcD4=
- 提示3：PHA+5ruR5Yqo5Y+Y6Zi75Zmo5ruR54mH5ZCRYeerr+enu+WKqO+8jOaOpeWFpeeUtei3r+eahOmYu+WAvOWPmOWwj++8jOeUtei3r+eUtea1geWPmOWkp++8jOeBr+azoeeahOWKn+eOh+WPmOWkpzwvcD4=
- 答案：RA==
PGRpdj7lvIDlhbPpl63lkIjliY3lsIbmu5Hliqjlj5jpmLvlmajpmLvlgLzosIPliLDmnIDlpKfvvIzlj6/ku6Xkv53miqTnlLXot6/vvIxB5q2j56GuPC9kaXY+PGRpdj7nlLHlm77nn6XmraTml7bnlLXmtYHkuLowLjNB77yM55S15Y6L5Li6Mi40Vu+8jOagueaNruWFrOW8j1I9VS9JIOWPr+W+l+eBr+azoeeUtemYu1I9OM6p77yMIELmraPnoa48L2Rpdj48ZGl2PuWmguaenOWwhua7keeJh1DlkJFh56uv5ruR5Yqo77yM77yM55S16Lev55qE55S15rWB5Y+Y5aSn77yM54Gv5rOh55S16Zi75LiN5Y+Y77yM5YiZ55S15Y6L6KGo55qE56S65pWw5bCG5Y+Y5aSn77yMQ+ato+ehrjwvZGl2PjxkaXY+5aaC5p6c5bCG5ruR54mHUOWQkWLnq6/mu5HliqjvvIznlLXot6/nmoTnlLXmtYHlh4/lsI/vvIzliJnlsI/nga/ms6HnmoTlrp7pmYXlip/njoflsIblsI/kuo7pop3lrprlip/njofvvIxE6ZSZ6K+vPC9kaXY+
本课配套习题挑战模式4/6
单选题
难度系数：
4.电现象中有三个同学们非常熟悉的实验：a、探究电流与电压的关系；b、伏安法测电阻； c、伏安法测电功率. 这三个实验均要多次测量电压与电流值，但对测量数据的处理方式并不相同. 下列说法正确的是（ ）
| A: a实验是为了多次测量求平均值来减小误差 |
| B: b实验是为了多次测量寻找普遍规律 |
| C: c实验是为了比较实际功率与额定功率 |
| D: 三个实验都是为了多次测量求平均值来减小误差 |
一次做对，真牛！
+5奖励规则>
- 提示1：IOWvueavj+S4quWunumqjOi/m+ihjOWIhuaekO+8jOaYjuehruWFtuWunumqjOebrueahO+8jOS7juiAjOehruWumuWvuea1i+mHj+aVsOaNruWkhOeQhuaWueW8j+S4jeWQjOeahOWOn+WboA==
- 答案：Qw==
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
本课配套习题挑战模式5/6
单选题
难度系数：
5.做伏安法测量小灯泡功率的实验，所测灯泡的额定电压是2.2V. 某同学连接的电路如图所示，当他合上开关时发现：灯不亮，电流表指针也不动，但电压表的指针接近满刻度. 他尝试移动滑动变阻器的滑动片P，仍不能改变以上现象. 你认为是下列哪种原因？（ ）
| A: 灯泡是坏的，或者灯泡与灯座接触不良 |
| B: 电流表接线柱没有拧紧，接触不良 |
| C: 电路的连接不正确 |
| D: 两节电池的电压太小，电路中电流很微弱 |
一次做对，真牛！
+5奖励规则>
- 提示1：IOeBr+azoeS4jeS6ruWPr+iDveaYr+eBr+azoeaWrei3r+aIlueBr+azoeS7peWklueahOWcsOaWueaWrei3r+aIlueBr+azoeefrei3rw==
- 提示2：IOeBr+azoeaWrei3r+aXtu+8jOeUtei3r+aWrei3r++8jOeUtei3r+S4reayoeacieeUtea1ge+8jOeUtea1geihqOaXoOekuuaVsO+8jOeUteWOi+ihqOS4suiBlOWcqOeUtei3r+S4re+8jOeUteWOi+ihqOa1i+mHj+eUtea6kOeUteWOiw==
- 提示3：IOeBr+azoeefrei3r+aXtu+8jOeUtei3r+aAu+eUtemYu+WHj+Wwj++8jOeUtei3r+eUtea1geWinuWkp++8jOeUtea1geihqOekuuaVsOWinuWkp++8jOeUteWOi+ihqOa1i+mHj+WvvOe6v+eUteWOi++8jOekuuaVsOS4ujAu
- 提示4：IOeBr+azoeS7peWklueahOWcsOaWueaWrei3r++8jOaVtOS4queUtei3r+mDveWkhOS6juaWreW8gOeKtuaAge+8jOeBr+azoeS4jeS6ru+8jOeUteWOi+ihqOWSjOeUtea1geihqOmDveayoeacieekuuaVsA==
- 答案：QQ==
PGRpdj7nlLXljovooajmnInnpLrmlbDvvIzor7TmmI7kuI7nlLXljovooajkuKTmjqXnur/ov57mjqXnmoTnlLXot6/mmK/pgJrot6/vvJvnga/ms6HkuI3kuq7vvIznlLXmtYHooajml6DnpLrmlbDvvIzor7TmmI7nlLXot6/mmK/mlq3ot6/vvIzmiYDku6XnlLXot6/mlYXpmpzmmK/nlLXljovooajlubbogZTnmoTpg6jliIbmlq3ot6/vvIznu5PlkIjpgInpobnlj6/nn6VB5q2j56Gu77yMQkNE5LiN5q2j56GuLiA8YnI+5pWF6YCJQS4gPC9kaXY+
本课配套习题挑战模式6/6
多选题
难度系数：
6.小明想测额定电压为3.8V小灯泡的额定功率，但他没有电流表，手边器材：电压表一块、滑动变阻器一个、阻值已知的定值电阻一个、符合要求的电源一块，导线和开关充足。小明认为测功率要根据P=UI，测不出电流，就没办法得到功率。对小明的说法正确的认识是（ ）
| A: 利用现有器材，合理组装电路，通过开关的断开或闭合，可以测出小灯泡的额定功率 |
| B: 小明的说法是正确的，测不出电流，得不到小灯泡的额定功率 |
| C: 如果没有阻值已知的定值电阻，就测不出小灯泡的额定功率 |
| D: 即使没有阻值已知的定值电阻，也可以测出小灯泡的额定功率 |
一次做对，真牛！
+5奖励规则>
- 提示1：IOW3suefpeeBr+azoeeahOmineWumueUteWOi++8jOa1i+W+l+atpOaXtueBr+azoeeahOeUtea1ge+8jOWNs+WPr+W+l+eBr+azoeeahOmineWumuWKn+eOhw==
- 提示2：IOWunumqjOayoeacieeUtea1geihqO+8jOS9huaYr+acieW3suefpemYu+WAvOeahOeUtemYu++8jOacieeUteWOi+ihqO+8jOWwseWPr+a1i+W+l+eUtei3r+S4reeahOeUtea1gQ==
- 答案：QSxD
PGRpdj7lt7Lnn6Xnga/ms6HnmoTpop3lrprnlLXljovvvIzmtYvlvpfmraTml7bnga/ms6HnmoTnlLXmtYHvvIzljbPlj6/lvpfnga/ms6HnmoTpop3lrprlip/njofvvIzkvYbmmK/lrp7pqozmsqHmnInnlLXmtYHooajvvIzmnInlt7Lnn6XpmLvlgLznmoTnlLXpmLvvvIzmnInnlLXljovooajvvIzlsLHlj6/mtYvlvpfnlLXot6/kuK3nmoTnlLXmtYHvvIzljbPlj6/mtYvlvpfnga/ms6HnmoTpop3lrprlip/njoc8L2Rpdj4=
