挑战习题
1/5单选题
难度:

1.用换元法解方程(x2+x)2+2(x2+x)-1=0,若设y=x2+x,则原方程可变形为()
A y2+2y+1=0
B y2-2y+1=0
C y2+2y-1=0
D y2-2y-1=0
提示1:
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正确答案:Qw==
PGRpdj7op6PvvJrnlKjmjaLlhYPms5XlsIZ5PXg8c3VwPjI8L3N1cD4reOS7o+WFpeWIsOWOn+aWueeoi++8iHg8c3VwPjI8L3N1cD4reO+8iTxzdXA+Mjwvc3VwPisy77yIeDxzdXA+Mjwvc3VwPit477yJLTE9MDwvZGl2PjxkaXY+5Y2z5Y+v5b6XIHk8c3VwPjI8L3N1cD4rMnktMT0wPC9kaXY+