1/3单选题
难度：
1.
函数ƒ (x)=−x2+4x−3 在区间
上的最大值和最小值分别是（ ）
| A | 1，0 |
| B | 3，—6 |
| C | 1，—8 |
| D | 1，—24 |
正确答案：Qw==
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
在区间
上的最大值、最小值分别是（ ） 
，0
，0
，
，则
的最小值是（ ） 